Respuesta :
59.43 grams of SiCl4 is formed when 10.0 grams of Si and 60.0
grams of Cl2 react.
Explanation:
Data given:
mass of Si = 10 grams
mass of chlorine gas = 60 grams
molar mass of Si = 28 grams/mole
molar mass of chlorine gas = 70.9 grams/mole
molar mass of Si[tex]Cl_{4}[/tex] = 169.8 grams/mole
Balanced equation:
Si + 2[tex]Cl_{2}[/tex] ⇒ Si[tex]Cl_{4}[/tex]
moles of Si = [tex]\frac{mass}{atomic mass of 1 mole}[/tex]
moles of Si = [tex]\frac{10}{28}[/tex]
moles of Si =0.35 moles
moles of chlorine gas = [tex]\frac{60}{70.9}[/tex]
moles of chlorine gas = 0.84 moles
from the balance reaction,
1 mole of Si gives 1 mole of Silicon tetrachloride
0.35 moles of Si will give 0.35 moles of silicon tetrachloride
mass = atomic mass x number of moles
mass = 169.8 x 0.35
mass = 59.43 grams
2 moles of chlorine gas gives 1 mole of silicon tetrachloride
0.84 moles of chlorine will give
0.84 x 2 moles= 1.68 moles of silicon tetrachloride
mass = 1.68 x 169.8
= 285.26 grams
Mass of silicon tetrachloride fromed is 59.43 grams as silicon is the limiting reagent.
