Answer:
[tex]\large \boxed{\text{381.7 mmHg}}[/tex]
Explanation:
Data:
p₁ = 694.9 mmHg; V₁ = 3.463 L
p₂ = ?; V₂ = 5.887 L
Calculation:
[tex]\begin{array}{rcl}p_{1}V_{1} & = & p_{2}V_{2}\\\text{648.9 mmHg} \times \text{3.463 L} & = & p_{2} \times\text{5.887 L}\\\text{2247.1 mmHg} & = & 5.887p_{2}\\p_{2} & = & \dfrac{\text{2247.1 mmHg}}{5.887}\\\\& = &\textbf{381.7 mmHg}\\\end{array}\\\text{The new pressure of the gas is $\large \boxed{\textbf{381.7 mmHg}}$}[/tex]
