Need help for 16) and 19) Solve each equation and check. Show all work please

Step-by-step explanation:
You said the other one would be the last haha just kidding I'm glad to help.
16. [tex]\frac{k}{2}=(-5)^2[/tex]
First, get rid of that parenthesis.
[tex]\frac{k}{2}=25[/tex]
Now multiply both sides by 2 so that you can isolate k
[tex]2(\frac{k}{2})=25*2[/tex]
[tex]k=50[/tex]
19. [tex]\frac{r}{3}=\frac{121}{11}[/tex]
This is a pretty easy one. If you didn't know, 121/11 is actually 11 :)
[tex]\frac{r}{3}=11[/tex]
Simply multiply by 3 to isolate r :)
[tex]3(\frac{r}{3})=11*3[/tex]
[tex]r=33[/tex]
Answer:
16) k = 50
19) r = 33
explanation:
16) -5 squared is 25
and then the two multiplies that 25 which equals 50
19) 121/11 = 11, which is then multiplied by 3 is 33