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What is the equation of a circle with a center at (-4,0)
t passes through the point (-2, 1)?
x2 + (y + 4)2 = square root 5
(x - 1)2 + (y + 2)2 = 5
(x + 4)2 + y2 = 5
(x + 2)2 + (y – 1)2 = square root 5

Respuesta :

valleybritney

Answer:

[tex](x+4)^2 + y^2 = 5[/tex]

Step-by-step explanation:

Circle equation: [tex](x-h)^2 + (y-k)^2 = r^2[/tex]

We need to find h, k , [tex]r^2[/tex] to complete the equation.

(h,k) is center point, in this case is given (-4,0) = (h,k)

h=-4

k=0

Substitute to equation: [tex](x+4)^2+(y-0)^2=r^2[/tex]

Use the initial condition: circle passes through the point (-2,1) = (x,y)

x=-2

y=1

Substitute to equation: [tex](-2+4)^2 + (1)^2=r^2[/tex]

Solve for [tex]r^2[/tex] = 5

Final answer: [tex](x+4)^2 + y^2 = 5[/tex]

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