Answer:
4095
Step-by-step explanation:
This can be evaluated by substituting n = 1 to n = 6 into the expression and summing the terms, that is
3([tex]4^{n-1}[/tex] )
= 3( [tex]4^{0}[/tex] + [tex]4^{1}[/tex] + 4² + 4³ + [tex]4^{4}[/tex] + [tex]4^{5}[/tex] )
= 3(1 + 4 + 16 + 64 + 256 + 1024)
= 3(1365)
= 3 × 1365
= 4095
