Which of the following is not an identity?
A. 2sin^2-X- Sinx=1
O B. sin^2x+ tan²x + cos^2x = sec^2x
O C. 2cos^2x-1 = 1 - 2 sin²x
O D. secx cscx(tanx+ cotx) = sec^2x + csc^2x

Respuesta :

Answer:

2sin^2x-sinx=1 aka A

Step-by-step explanation:

A P E X

2sin^2-X- Sinx=1 and secx cscx(tanx+ cotx) = sec^2x + csc^2x is not an identity. Option A and D is correct.


Four options are given, which of them is not an identity is to be determined.


What is identity?

An identity is the common case formula that helps to solve mathematics.

1) 2sin^2-X- Sinx=1

Its not an identity cause it is form of equation and contain -x.

2) sin^2x+ tan²x + cos^2x = sec^2x
   sIn^2x + cos^2x = sec^2x -tan^2x
                        1      =      1
It is a perfect identity.

3) 2cos^2x-1 = 1 - 2 sin²x

     cos2x =cos2x
It is also a perfect identity.

4) secx cscx(tanx+ cotx) = sec^2x + csc^2x
    secx cscx  (sinx/cos x + cosx/sinx) = sec^2 + csc^2x
    secx cscx (sin^x+cox^2x/cosxsinx) = sec^2x +csc^2x
      It is also not an identity.

Thus,  2sin^2-X- Sinx=1 and secx cscx(tanx+ cotx) = sec^2x + csc^2x is not an identity. Option A and D is correct.

Learn more about identity here:
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