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The potential energy of an object attached to a spring is 2.60 J at a location where the kinetic energy is 1.40 J. If the amplitude ???? of the simple harmonic motion is 16.0 cm, calculate the spring constant ???? and the magnitude of the largest force ????spring, max that the object experiences.

????= Nm

????spring, max= N

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Answer:

This is the equation for elastic potential energy, where U is potential energy, x is the displacement of the end of the spring, and k is the spring constant. 

 U = (1/2)kx^2 

 U = (1/2)(5.3)(3.62-2.60)^2 

 U =  2.75706 J

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