Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.

q = 55 StartRoot 5 EndRoot
q = -5Negative 5 StartRoot 5 Endroot
q = 33 StartRoot 5 Endroot
q = -3Negative 3 StartRoot 5 EndRoot
q = 2525 StartRoot 5 EndRoot

Respuesta :

Answer:

[tex]5\sqrt{5}[/tex] and [tex]-5\sqrt{5}[/tex]

Step-by-step explanation:

We want to find roots of the function: [tex]f(q)=q^2-125[/tex]. The roots are the numbers that make the function f(q) = 0. So set the expression equal to 0:

[tex]q^2-125=0[/tex]

Add 125 to both sides:

[tex]q^2=125[/tex]

Square root both sides:

[tex]q=[/tex] +/- [tex]\sqrt{125}[/tex] = +/- [tex]\sqrt{5^2*5}[/tex] = +/- [tex]5\sqrt{5}[/tex]

So, the answers are [tex]5\sqrt{5}[/tex] and [tex]-5\sqrt{5}[/tex]. (Sorry, I can't tell what the answer choices are)

Hope this helps!

Answer:

q = 5 startroot 5 endroot

q = Negative 5 startroot 5 endroot

Step-by-step explanation:

q² - 125 = 0

q² = 125

q = +/- sqrt(125)

q = +/- 5sqrt(5)

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