The frequency and energy ranges of photons in some parts of the electromagnetic spectrum are given in the table above. Which of the following could be the energy of a photon in the visible range?

The energy of a photon is given by the wavelength of the photon, where the lower the wavelength the higher the energy is. Therefore, photons in the infrared range have the lowest energy and photons in the ultraviolet range have the highest energy. A photon in the visible range must have an energy which is between the infrared range and the ultraviolet range. Since the maximum energy of a photon in the infrared range is 3 x 10-19 J and the minimum energy of a photon in the ultraviolet range is 5 x 10-19 J, a photon in the visible range could have an energy of 4 x 10-19 J.

kasliwalalvi24 kasliwalalvi24 · Answer 2 · 2021-10-06T13:41:45+02:00

Answer:

The energy of photon in visible range will be [tex]4 * 10 ^{-19}[/tex].

Explanation:

The photons are inversely proportional to the wavelength, such that the photons with highest energy will have lowest wavelength. For instance, the photons of infrared range have lowest energy, whereas the photons in UV range will have highest energy. Thus, a photon belonging to the visible range should have the energy between infrared and UV region. Since, as given in the question, the maximum energy of photon in UV range is [tex]3 * 10^{-19}[/tex] J whereas the minimum energy of photon in UV range is [tex]5 * 10^{-19}[/tex] . Therefore, the photons in the visible range could possible have energy of [tex]4 * 10 ^{-19}[/tex] J.

For Further Reference:

https://brainly.com/question/3776320?referrer=searchResults