Respuesta :
108.05 grams of NH4NO3 would you need to decompose to inflate your air bag to the correct size with 59.6g of dinitrogen monoxide.
Explanation:
Data given:
mass of dinitrogen monoxide = 59.6 grams
atomic mass of dinitrogen monoxide = 44.01 grams/mole
grams of N[tex]H_{4}[/tex]N[tex]O_{3}[/tex] = ?
atomic mass of ammonium nitrate = 108.05 grams/mole
balanced chemical equation:
N[tex]H_{4}N_{} O_{3}[/tex] ⇒ [tex]N_{2}[/tex]O +2 [tex]H_{2}[/tex]O
Firstly the number of moles will be calculated from the given mass by using the formula:
number of moles = [tex]\frac{mass}{atomic mass of 1 mole}[/tex]
putting the values in the equation:
number of moles = [tex]\frac{59.6}{44.01}[/tex]
number of moles = 1.35 moles
from the balanced equation :
1 mole of ammonium nitrate decomposes to release 1 mole of dinitrogen monoxide
so, 1.35 moles will give 1.35 moles of dinitrogen monoxide.
mass = atomic mass x number of moles
mass = 80.043 x 1.35
mass = 108.05 grams of ammonium nitrate.
