Respuesta :
1. 96.882 grams of Zinc Sulfate are produced and 0.0012 litres of hydrogen is gas formed.
2 . 46.65 grams is the mass of carbon dioxide gas formed and its volume is 23.74 litres.
Explanation:
1) Data given:
volume of Sulphuric acid = 100 ml or 0.1 litre
molarity of sulphuric acid = 6M , number of moles of sulphuric acid = 0.6 moles
number of moles = molarity x volume
6 x 0.1
number of moles = 0.6
Zinc sulphate formed =?
hydrogen gas released =?
balanced chemical reaction
Zn + [tex]H_{2} S_{} O_{4}[/tex] ⇒ ZnS[tex]O_{4}[/tex] +
1 mole of sulphuric acid reacted it formed 1 moles of zinc sulphate and 1 mole of hydrogen gas
so, 0.6 moles of sulphuric acid will give 0.6 moles of zinc sulphate and 0.6 mole of hydrogen gas.
mass = atomic mass x number of moles
mass = 161.47 x 0.6
mass of zinc sulphate formed =96.882 grams
litres of hydrogen gas formed = 0.6 x 2
= 1.2 ml
hence 0.0012 litres of hydroge gas formed
2) Data given:
mass of barium carbonate = 211 grams
atomic mass of barium carbonate = 197.34 grams/mole
balanced reaction:
BaC[tex]O_{3}[/tex] + 2HN[tex]O_{3}[/tex] ⇒ Ba(N[tex]O_{3}[/tex])2 +C [tex]O_{2}[/tex] + [tex]H_{2}[/tex]O
number of moles of barium carbonate = [tex]\frac{mass}{atomic mass of 1 mole}[/tex]
putting values in the equation:
number of moles = [tex]\frac{211}{197.34}[/tex]
= 1.06 moles
from the reaction
1 mole of BaCO3 reacted to give 1 mole barium nitrate and 1 mole of carbon dioxide gas
so 1.06 moles of BaCO3 will give 1.06 moles each barium nitrate and carbon dioxide gas
mass = atomic mass x number of moles
mass of carbon dioxide = 1.06 x 44.01
= 46.65 grams
assuming CO2 at STP, we apply ideal gas law
PV = nRT
here T = 273 K, P= 1 atm, R= 0.08201 L atm/mole K
V = [tex]\frac{nRT}{P}[/tex]
V = [tex]\frac{1.06 x 0.08201X 273}{1}[/tex]
V = 23.74 Litres
Answer:
1. 96.882 grams of Zinc Sulfate are produced and 0.0012 liters of hydrogen is gas formed.
2 . 46.65 grams is the mass of carbon dioxide gas formed and its volume is 23.74 liters.
Explanation:
1) Data given:
volume of Sulphuric acid = 100 ml or 0.1 liter
molarity of sulphuric acid = 6M , number of moles of sulphuric acid = 0.6 moles
number of moles = molarity x volume
6 x 0.1
number of moles = 0.6
Zinc sulphate formed =?
hydrogen gas released =?
balanced chemical reaction
Zn + ⇒ ZnS +
1 mole of sulphuric acid reacted it formed 1 moles of zinc sulphate and 1 mole of hydrogen gas
so, 0.6 moles of sulphuric acid will give 0.6 moles of zinc sulphate and 0.6 mole of hydrogen gas.
mass = atomic mass x number of moles
mass = 161.47 x 0.6
mass of zinc sulphate formed =96.882 grams
liters of hydrogen gas formed = 0.6 x 2
= 1.2 ml
hence 0.0012 liters of hydrogel gas formed
2) Data given:
mass of barium carbonate = 211 grams
atomic mass of barium carbonate = 197.34 grams/mole
balanced reaction:
BaC + 2HN ⇒ Ba(N)2 +C + O
number of moles of barium carbonate =
putting values in the equation:
number of moles =
= 1.06 moles
from the reaction
1 mole of BaCO3 reacted to give 1 mole barium nitrate and 1 mole of carbon dioxide gas
so 1.06 moles of BaCO3 will give 1.06 moles each barium nitrate and carbon dioxide gas
mass = atomic mass x number of moles
mass of carbon dioxide = 1.06 x 44.01
= 46.65 grams
assuming CO2 at STP, we apply ideal gas law
PV = nRT
here T = 273 K, P= 1 ATM, R= 0.08201 L ATM/mole K
V =
V =
V = 23.74 Liters
Explanation:
Brainliest?
