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osikbro

Answer:

Side AB is approximately 89.067m, while side BC is approximately 136.459m.

Step-by-step explanation:

The first step is to find the value of angle A. 180-60-40=80°. Now, you can use  the Law of Sines to find that [tex]\frac{\sin(60^\circ)}{120}=\frac{\sin(80^\circ)}{x}=\frac{\sin(40^\circ)}{y}[/tex]. Cross multiplying, you find that [tex]x=\frac{\sin(80^\circ)\cdot120}{\sin(60^\circ)}\approx 136.459[/tex]. Similarly, [tex]y=\frac{\sin(40^\circ)\cdot120}{\sin(60^\circ)}\approx 89.067[/tex]. PM me if you have any questions!

Cetacea

Answer:

[tex]BC\ =136.458965112\\AB=89.0672638762[/tex]

Given B = 60, C = 40.

Sum of three angles = 180 degree.

So, A = 180 - 60 - 40 = 80 degree.

We will use law of sine to find the missing sides.

[tex]\frac{120}{\sin60}=\frac{BC}{\sin80}=\frac{AB}{\sin40}[/tex]

Solving this equation we get:

[tex]BC\ =\ \frac{120}{\sin60}\cdot\sin80=136.458965112\\AB=\ \frac{120}{\sin60}\cdot\sin40=89.0672638762[/tex]

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