Answer: 3.23 g/L
Explanation:
P1= 650 kPa
P2= 200 kPa
S1= 10.5 g/L
S2= ?
S2 = P2 x S1/P1
S2 = ( 200 kPa x 10.5 g/L)/(650 kPa)
S2 = 3.23 and since we are looking for the solubility of the gas when the pressure is 200 kPa, so we use g/L, 3.23 g/L.
Hope this helped! :)
