Answer:
a) [tex]k \approx \frac{\sqrt{3}}{3}[/tex], b) [tex]\left(\frac{\sqrt{3}}{3}, \frac{1}{3} \right)[/tex]
Step-by-step explanation:
a) The constant of proportionality is:
[tex]k = \frac{y}{x}[/tex]
[tex]k = \tan \theta[/tex]
[tex]k = \tan \frac{\pi}{6}[/tex]
[tex]k \approx \frac{\sqrt{3}}{3}[/tex]
b) The ordered pair is:
[tex]\left(\frac{\sqrt{3}}{3},\frac{\sqrt{3}}{3}\cdot \frac{\sqrt{3}}{3} \right)[/tex]
[tex]\left(\frac{\sqrt{3}}{3}, \frac{1}{3} \right)[/tex]
