Answer:
angle between the red and blue = 1.26°
Explanation:
given data
Refractive index For blue = 1.650
Refractive index For red = 1.610
Incident angle = 30°
solution
we will Use here Snell's law that is express as
[tex]\frac{\sin{i}}{\sin{r}}[/tex] = n .................1
so we get here refraction angle for both blue and red
so for blue ray it will be put value in equation 1
[tex]\dfrac{\sin{i}}{\sin{r_{b}}} = n(blue)[/tex]
[tex]\frac{\sin{30}}{\sin{r_{b}}}[/tex] = 1.650
[tex]sin({r_{b}})[/tex] = 0.3030
[tex]{r_{b}}[/tex] = 17.64°
and
for red ray it will be put value in equation 1
[tex]\frac{\sin{30}}{\sin{r_{r}}}[/tex] = 1.610
[tex]\sin({r_{r}} )[/tex] = 0.3105
[tex]r_{r}[/tex] = 18.09°
so
angle between the red and blue will be as
angle between the red and blue = [tex]r_{r} - {r_{b}}[/tex] ................2
put here value
angle between the red and blue = 18.09° - 17.64°
angle between the red and blue = 1.26°
