Answer:
(a) Magnetic force [tex]F=38.584\times 10^{-19}N[/tex]
(b) Acceleration [tex]a=5.846\times 10^8m/sec^2[/tex]
(C) Speed will remain same
Explanation:
We have given velocity of alpha particle v = 520 m/sec
Magnetic field B = 0.034 T
Charge on alpha particle [tex]q=3.2\times 10^{-19}C[/tex]
Mass of alpha particle [tex]m=6.6\times 10^{-27}kg[/tex]
Angle between velocity and magnetic field 43°
(a) Force acting on the particle is equal to
[tex]F=q(v\times B)=qvBsin\Theta[/tex]
[tex]F=3.2\times 10^{-19}\times 320\times 0.034\times sin43^{\circ}[/tex]
[tex]F=38.584\times 10^{-19}N[/tex]
(B) According to newton's law
F = ma. here m is mass and a is acceleration.
So acceleration
[tex]a=\frac{F}{m}=\frac{38.584\times 10^{-19}}{6.6\times 10^{-27}}=5.846\times 10^8m/sec^2[/tex]
(c) As the magnetic force is always perpendicular to velocity so speed will remain same neither decreases nor increases.
