Hot-air balloons rise because the hot air inside the balloon is less dense than the cooler air outside. Calculate the volume an air sample will occupy inside a balloon at 43.0C if it occupies 2.50L at the outside air temperature of 22.0C, assuming the pressure is the same at both locations

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Answer:

[tex]V_2=2.68L[/tex]

Explanation:

Hello,

In this case, we use the Charles' law which allows us to understand the volume-temperature behavior as gas has as a directly proportional relationship:

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

Whereas the temperature must be in absolute units such as Kelvin. Hence, solving for the volume at 43.0 °C, we obtain:

[tex]V_2=\frac{V_1T_2}{T_1}=\frac{2.50L*(43.0+273.15)K}{(22.0+273.15)K} \\\\V_2=2.68L[/tex]

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