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A fish lies 42 cm below the surface of a clear pond. If the index of refraction of water is assumed to be 1.33 and that of air is approximately 1, how far below the surface does the fish appear to a person looking down from above

Respuesta :

Answer:

Apparent depth = 31.58 cm

Explanation:

given data

fish lies below the surface D = 42 cm  

index of refraction n = 1.33

solution

we get here Apparent depth that is express as

index of refraction = Actual depth ÷  Apparent depth   ..............1

put here value and we get Apparent depth

1.33 =  42 ÷ Apparent depth  

solve it we get

Apparent depth = [tex]\frac{42}{1.33}[/tex]    

Apparent depth = 31.58 cm

The fish appear to a person looking down is 31.58 cm far from above.

 

Given here,  

Fish lies below the surface D = 42 cm    

Index of refraction n = 1.33

 

Apparent depth can be calculated by the formula,  

[tex]\bold {n =\dfrac { Real\ depth}{ Apparent\ depth}}[/tex]

Or,

[tex]\bold { Apparent\ depth =\dfrac { Real\ depth}{ n}}[/tex]

put the value and calculate for Apparent depth,

[tex]\bold { Apparent\ depth =\dfrac { 42}{ 1.33}}\\\\\bold { Apparent\ depth = 31.58 cm}[/tex]

Therefore, the fish appear to a person looking down is 31.58 cm far from above.

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