Answer:
Explanation:
Given that,
Fax machine uses a current of 0.106A on normal mode
I = 0.106A
The fax machine uses a current of 0.04A on stand by mode
I' = 0.04A
The potential different is 240V
V = 120V
A. In one minute, charges that pass through the fax machine between the standby mode and normal mode
t = 1minute = 60seconds
Charge is given
Q = it
So, the charge that pass through the fax machine is
Q = It — I't
Q = (I — i') t
Q = (0.106 — 0.04) × 60
Q = 3.96C
B. Work in electric field is given as
W = QV
Where
W = work
Q = charge
V = potential difference
W = 3.96 × 120
W = 475.2 J
