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If we start with 400 atoms of a radioactive substance, how many would remain after one half-life? After 2 half-lives? After 3 half-lives? After 4 half-lives?

Respuesta :

Answer:

how many would remain

after one half-life = 200 atoms

After 2 half-lives = 100 atoms

After 3 half-lives = 50 atoms

After 4 half-lives = 25 atoms

Explanation:

Given;

Initial amount = 400 atoms

Half life is the time taken to decay half of a radioactive material.

how many would remain after one half-life;

= 400/2 = 200 atoms

After 2 half-lives;

= 400/2^2 = 400/4

= 100 atoms

After 3 half-lives

= 400/2^3 = 400/8

= 50 atoms

After 4 half-lives

= 400/2^4 = 400/16

= 25 atoms

The half-life is the time it takes the number of atoms to remain half of the

initial number of atoms.

  • Number of atoms remaining after 2 half lives are 100 atoms
  • Number of atoms remaining after 3 half lives are 50 atoms
  • Number of atoms remaining after 4 half lives are 25 atoms

Reasons:

The initial number of radioactive atoms, N₀ = 400

Required:

The number of atoms that will remain after 2 half lives?

Solution:

Half life is given by the formula;

[tex]N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}}[/tex]

After 2 half lives, we have;

t = 2 × [tex]t_{1/2}[/tex]

Which gives;

[tex]N(2 \times t_{1/2}) = 400 \times \left (\dfrac{1}{2} \right )^{\dfrac{2 \times t_{1/2}}{t_{1/2}}} = 400 \times \left (\dfrac{1}{2} \right )^2 = 100[/tex]

The number of atoms remaining after 2 half lives = 100

After 3 half-lives, we have;

[tex]N(3 \times t_{1/2}) = 400 \times \left (\dfrac{1}{2} \right )^{\dfrac{3 \times t_{1/2}}{t_{1/2}}} = 400 \times \left (\dfrac{1}{2} \right )^3 = 50[/tex]

The number of atoms remaining after 3 half lives = 50

After 4 half-lives, we have:

[tex]N(4 \times t_{1/2}) = \mathbf{400 \times \left (\dfrac{1}{2} \right )^{\dfrac{4 \times t_{1/2}}{t_{1/2}}}} = 400 \times \left (\dfrac{1}{2} \right )^4 = 25[/tex]

The number of atoms remaining after 4 half lives = 25

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