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A newspaper plans to conduct a survey for the upcoming presidential election in order to estimate the proportion of the population, p, who supports a certain candidate. What is the smallest sample size needed to obtain an estimate that is within 4% of the true proportion p at the 96% confidence level

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Answer:

660

Step-by-step explanation:

For the newspaper survey, the smallest sample size needed with confidence level 96 percent is 657.

What is sample size?

Sample size is the number of persons, groups, or the data which is required to conduct a survey.

The sample size can be calculated as,

[tex]n=\dfrac{z^*}{M}\overline p(1-\overline p)[/tex]

Here, M is the margin or error and p bar is the estimate value of proportion.

A newspaper plans to conduct a survey for the upcoming presidential election in order to estimate the proportion of the population, p, who supports a certain candidate.

The true proportion p at 4% and the value of confidence level is 96%The value of z score at 96 percent of confidence level is 2.05.

As there is no estimation given, thus we use 0.50 proportion for a conservative estimate.

[tex]n=(\dfrac{2.05}{0.04})^2(0.5)(1-0.5)\\n\cong657[/tex]

Hence, for the newspaper survey, the smallest sample size required with confidence level 96 percent is 657.

Learn more about the sample size here;

https://brainly.com/question/14470673

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