Respuesta :
Answer:
[tex]\lambda=630 nm[/tex]
Explanation:
The equation of the fringe in a double slit experiment is given by:
[tex]y=\frac{m\lambda D}{d}[/tex] (1)
here:
- y is the distance between bright fringes (two adjacent bright fringes distance = 4.9 mm).
- m is a natural number, related to the bright fringes in a diffraction pattern, in our case we use m=1
- D is the distance between the screen and the double slit (D=1.4 m)
- d is the distance between the slits (d=0.18 mm)
- λ is the wave length of the laser.
Therefor we just need to solve the equation (1) for λ:
[tex]\lambda=\frac{d*y}{D}[/tex]
[tex]\lambda=\frac{0.00018*0.0049}{1.4}[/tex]
[tex]\lambda=6.3*10^{-7}m[/tex]
[tex]\lambda=630 nm[/tex]
I hope it helps you!
Answer:
6.3*10^-7m
Explanation:
to find the wavelength of the laser you can use the following formula:
[tex]y=\frac{m\lambda D}{d}[/tex]
y: height from the center of the screen to a fringe
m: order of the fringe
D: distance to the screen = 1.4m
d: distance between slits = 0.18mm
you know the separation of two fringes. Hence, you can use two consecutive fringes to find the wavelength in the following way:
[tex]\Delta y=\frac{m\lambda D}{d}-\frac{(m-1)\lambda D}{d}=\frac{\lambda D }{d}\\\\\lambda=\frac{\Delta y d}{D}=\frac{(4.9*10^{-3}m)(0.18m*10^{-3}m)}{1.4m}=6.3*10^{-7}m[/tex]
hence, the walength is 6.3*10^-7m