contestada


"How many formula units are there in sample of copper(II) sulfate that has
a mass of 32.5 grams?" *
8.16E(-24) formula units CuSO4
O
1.23E23 formula units CuSO4
O
3.38E(-25) formula units Cus04
2.96E24 formula units CuSO4

Respuesta :

Answer: [tex]1.23\times 10^{23}[/tex] formula units

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{32.5g}{160g/mol}=0.203moles[/tex]

1 mole of [tex]CuSO_4[/tex] contains [tex]6.023\times 10^{23}[/tex] of formula units

Thus 0.203 mole of [tex]CuSO_4[/tex] contains =[tex]\frac{6.023\times 10^{23}}{1}\times 0.203=1.23\times 10^{23}[/tex] of formula units