Respuesta :
Answer:
A
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Given (h, k) = (0, - 7) and r = 11, then
(x - 0)² + (y - (- 7))² = 11², that is
x² + (y + 7)² = 121 → A
The equation of the circle with radius, r = 11 , and the center at (0, - 7) is A. [tex]x^{2} + (y+7)^{2} = 121[/tex]
What is a circle?
- A round plane figure whose boundary (the circumference) consists of points equidistant from a fixed point (the center) is called a circle.
- Standard equation of the circle can be given in the form
[tex](x - h)^{2} +(y-k)^{2} = a^{2}[/tex] where (h,k) is the center and a is the radius.
How to find the equation of the circle with radius, r = 11 , and the center at (0, - 7)?
Comparing with the standard equation, we get,
- h = 0 and k = -7
- radius = a = 11
Putting these values in the standard equation we get,
[tex](x-0)^{2} +(y + 7)^{2} = 121[/tex]
⇒ [tex]x^{2} + (y+7)^{2} = 121[/tex]
The equation is [tex]x^{2} + (y+7)^{2} = 121[/tex]
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