Answer:
A) [tex]-11.136[/tex]
B) [tex]-11.136[/tex]
C) [tex]139.2[/tex] N
Explanation:
A )
Change in momentum is equal to Final momentum - Initial momentum
Final momentum
[tex]= 0.174 * 26\\= 4.524\\[/tex]
Initial Momentum
[tex]= 0.174 * -38\\= - 6.612[/tex]
Thus, Change in momentum
[tex]= (-6.612- 4.525 )\\= - 11. 136\\[/tex]
B) Impulse delivered by bat is equal to the change in momentum i.e [tex]- 11. 136[/tex]
C) Force is equal to change in momentum divided by time
Force [tex]= \frac{-11.136}{80 * 10^{-3}} \\= 139.2[/tex]
Force exerted by bat on ball is[tex]139.2[/tex] N
The change in the momentum of the softball is 11.136 kgm/s.
The impulse delivered by the bat is 11.136 kgm/s.
The average force the bat exerts on the ball at the given time is 13,920 N.
The given parameters:
The change in the momentum of the softball is calculated as follows;
[tex]\Delta P = m\Delta v\\\\ \Delta P = m (v_1- v_2)\\\\ \Delta P = 0.174 (26 - -38)\\\\ \Delta P = 0.174(64)\\\\ \Delta P = 11.136 \ kgm/s[/tex]
The impulse delivered by the bat is equal to change in momentum of the ball = 11.136 kgm/s.
The average force the bat exerts on the ball at the given time is calculated as follows;
[tex]F = \frac{\Delta P}{t} \\\\ F = \frac{11.136}{0.8 \times 10^{-3} } \\\\ F = 13,920 \ N[/tex]
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