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What is x^2-11x-5=0

Solve in a quadratic formula, and the answer has to have the use of integers or fractions. No DECIMALS. I need this fast!!!

Respuesta :

nktselepov

[tex]x^2-11x-5=0\\a=1,b=-11,c=-5\\D=b^2-4ac=(-11)^2-4\times1\times(-5)=121+20=141\\x_{1,2}=\dfrac{-b\pm\sqrt{D} }{2a} \\x_1=\dfrac{11+\sqrt{141} }{2} \\x_2=\dfrac{11-\sqrt{141} }{2}[/tex]

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