Respuesta :

Wallind11

Answer:

AB²=AC²+ BC²

[tex]AB = \sqrt{ {(8)}^{2} + {(15)}^{2} } [/tex]

[tex] = \sqrt{64 + 225} = \sqrt{289} = 17[/tex]

AB(hypotenuse)=17cm

Kritu3

Answer:

Step-by-step explanation:

Here Given

perpendicular (p)= 15 cm

base (b) = 8 cm

hypotenuse (h) = ?

We know by using Pythagoras theorem,

[tex]h^{2} =p^{2} +b^{2}[/tex]

[tex]h^{2} = 15^{2} + 8^{2}[/tex]

[tex]h^{2} = 225 +64[/tex]

[tex]h^{2} = 289[/tex]

[tex]h =\sqrt{289}[/tex]

Therefore h = 17 cm

Hope it will help :)

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