Answer:
367.7466 g of potassium chlorate is produced.
Explanation:
Given data:
223.65 g of potassium chloride is produced
Question: How much potassium chlorate did the reaction start with, mKClO₃ = ?
The balanced reaction:
2KClO₃ → 2KCl + 3O₂
Information needed:
Molecular weight of KClO₃ = 122.5 g/mol
Molecular weight of KCl = 74.5 g/mol
Molecular weight of O₂ = 32 g/mol
You can see in the reaction that 2 moles of KClO₃ gives 2 moles of KCl.
Mass of KClO₃:
[tex]m_{KClO_{3} } =2*122.5=245g[/tex]
Mass of KCl:
[tex]m_{KCl } =2*74.5=149g[/tex]
245 g KClO₃ --------- 149 g KCl
X g KClO₃ ------------- 223.65 g KCl
[tex]X=m_{KClO_{3} } =\frac{245*223.65}{149} =367.7466g[/tex]
