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A fair six-sided die is tossed twice.What is the probability of the first toss will be a number less than 3, and the second toss will be a number greater than 3?

Respuesta :

Answer:

Step-by-step explanation:

on the first toss it would be out of 6 so it would be 3/6

for the second it would be out of 6 again and it would be 3/6

but if you have to double them up then they would both be 6/12

and if you need to simplify it would be equivalent to 1/2

EspionageGirl

Answer:

1st toss: 3/6

2nd toss: 3/6

All: 1/2

Step-by-step explanation:

On the first toss, it would be 3/6 because it is out of 6. For the second toss, it is out of 6 again so it is still 3/6. Since you want to know what the probability is when it is tossed twice, we multiply it by 2 and get 6/12. Either way, it is equivalent to 1/2. I hope this helps. Please mark me brainliest because lots of people have scammed me. I really need it. Please and thank you!

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