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Part A)) Determine the equivalent resistance of 25 Ω and 15 Ω in series. ReqA=?

Part B)) determined equivalent resistance of 220 Ω and 430 Ω in parallel. ReqB=?

Two questions please help

Respuesta :

clara856

Explanation:

part A

series. combination of resistance

R=R1+R2

given R1=25 and R2=15

R=25+15

R=40

partB

parallel combination of resistance

given R1=220 and R2=430

R=1/R1 +1/R2

R=1/220+1/430

R=13/1892

a. The equivalent resistance should be 40.

b. The equivalent resistance should be 13/1892.

Calculation of the equivalent resistance:

Resistance determined the opposite with respect to the current flow in the electrical circuit. It should be calculated in ohms.

a. Since the resistance are 25 Ω and 15 Ω

So,

R=R1+R2

R=25+15

R=40b.

Now the resistance is 220 Ω and 430 Ω in parallel

So,

R=1/R1 +1/R2

R=1/220+1/430

R=13/1892

In this way, the equivalent resistance should be measured.

Learn more about resistance here: https://brainly.com/question/24462138

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