The Duck Pond game at the carnival has a pool with 75 toy ducks. Twenty-five of these ducks are marked underneath as winners. To play, you pick up a duck, do not replace it, then pick up another. What is the probability that both ducks picked are winners?

Respuesta :

Answer:

4/37

Step-by-step explanation:

First, let's get the probability that the first duck is a winner.

number of winner ducks / number of all ducks =

25 / 75 = 1/3.

Okay, so we know the first duck probability. But for the second, we need to keep in mind that there are now only 74 ducks in the pool, and only 24 ducks are winners (given that we've already picked one winner).

new number of winner ducks / new number of all ducks =

24 / 74 = 12/37.

These are independent events, so we need to multiply them together for our answer.

1/3 * 12/37 = 4/37

the probability that both ducks picked are winners is 4 by 37

  • The calculation is as follows:

here let's get the probability that the first duck is a winner.

So,  

[tex]= 25 \div 75 \\\\= 1\div3[/tex]

Okay, so we know the first duck probability.

But for the second, we need to keep in mind that there are now only 74 ducks in the pool, and only 24 ducks are winners

So,  

[tex]= 24 \div 74 \\\\= 12\div37[/tex]

These are independent events, so we need to multiply them together

[tex]= 1\div 3 \times 12\div 37 \\\\= 4\div 37[/tex]

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