An old bone contains 80% of its original carbon-14. Use the half-life model to find the age of the bone. Find an equation equivalent toP (t) = A (one-half) Superscript StartFraction t Over 5,730 EndFraction

Respuesta :

First Part: D    P(t)/A=(1/2)^t/5,730

Second Part: 0.8

Third Part: B    about 1,845 years

The equivalent equation of [tex]P(t) = A(\frac 12)^{\frac{t}{5730}}[/tex] is [tex]\frac{P(t)}A = (\frac 12)^{\frac{t}{5730}}[/tex]

How to determine the equivalent equation?

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The equation is given as:

[tex]P(t) = A(\frac 12)^{\frac{t}{5730}}[/tex]

Divide both sides of the equation by A

[tex]\frac{P(t)}A = (\frac 12)^{\frac{t}{5730}}[/tex]

This means that the equivalent equation of [tex]P(t) = A(\frac 12)^{\frac{t}{5730}}[/tex] is [tex]\frac{P(t)}A = (\frac 12)^{\frac{t}{5730}}[/tex]

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