Respuesta :
Answer:
1) x ≤ 2 or x ≥ 5
2) -6 < x < 2
Step-by-step explanation:
1) We have x^2 - 7x + 10, so let's factor this as if this were a regular equation:
x^2 - 7x + 10 = (x - 2)(x - 5)
So, we now have (x - 2)(x - 5) ≥ 0
Let's imagine this as a graph (see attachment). Notice that the only place that is above the number line is considered greater than 0, and that's when x ≤ 2 or x ≥ 5 (the shaded region).
2) Again, we have x^2 + 4x - 12, so factor this as if this were a regular equation:
x^2 + 4x - 12 = (x + 6)(x - 2)
So now we have (x + 6)(x - 2) < 0
Now imagine this as a graph again (see second attachment). Notice that the only place that is below 0 (< 0) is when -6 < x < 2 (the shaded region).
Hope this helps!


Answer:
1. x ≤ 2 or x ≥ 5
2. -6 < x < 2
Step-by-step explanation:
1) x^2 - 7x+10 ≥ 0
Find the roots
x² - 7x + 10 = 0
x² - 5x - 2x + 10 = 0
x(x - 5) - 2(x - 5) = 0
(x - 2)(x - 5) = 0
x = 2, 5
It's an "or" case.
x ≤ 2 or x ≥ 5
2) x^2 +4x-12<0
Find the roots
x² + 4x - 12 = 0
x² + 6x - 2x - 12 = 0
x(x + 6) - 2(x + 6) = 0
(x - 2)(x + 6) = 0
x = 2, -6
It's an "and" case.
-6 < x < 2