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Identify the species that was reduced in the titration reaction shown below. Justify your answer in terms of oxidation numbers.
6H+(aq)+2MnO4−(aq)+5H2C2O4(aq)→10CO2(g)+8H2O(l)+2Mn2+(aq)

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Answer:

MnO₄⁻ is species reduced as manganese gains 5e⁻ and is reduced to Mn⁺²

Explanation:

MnO₄⁻ + 5e⁻ => Mn⁺²

Mn + 4O = -1

Mn + 2(-2) = - 1

Mn = +7

Mn = +7 gains 5e⁻ => Mn = +2

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