Respuesta :

sweetart123
The answer would be A) tan A, because of SOHCAHTOA (if you don't know this, it means SOH) sin=opposite/hypotenuse, CAH) cos=adjacent/hypotenuse, and TOA) tan=opposite/adjacent).
calculista

we know that

In the right triangle ABC

[tex]sin(A)=\frac{BC}{AC}= \frac{a}{b}[/tex]

[tex]cos(A)=\frac{AB}{AC}= \frac{c}{b}[/tex]

[tex]tan(A)=\frac{BC}{AB}= \frac{a}{c}[/tex]

[tex]sin(C)=\frac{AB}{AC}= \frac{c}{b}[/tex]

[tex]cos(C)=\frac{BC}{AC}= \frac{a}{b}[/tex]

[tex]tan(C)=\frac{AB}{BC}= \frac{c}{a}[/tex]

therefore

the answer is the option A

[tex]tan(A)[/tex]

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