1 pts

What is the distance (in meters) of an object that has an angular diameter of 75 arcseconds and a linear diameter of 65 meters?

Respuesta :

Answer:

The distance of the object in meters is 0.02364 m

Explanation:

Given;

angular diameter of the object, θ = 75 arcseconds = [tex]\frac{75}{3600}[/tex]

linear diameter of the object, α = 65 meters

distance of the object in meters, L = ?

The distance of the object in meters can be calculated by using the formula below;

[tex]L= 2 \alpha*tan\frac{\theta}{2}[/tex]

where;

L is distance of the object in meters

α is linear diameter of the object

θ is angular diameter of the object

Substitute these given values and calculate the distance

[tex]L = 2*65*tan(\frac{75}{2*3600} ) = 0.02364 \ m[/tex]

Therefore, the distance of the object in meters is 0.02364 m