a 2.0 L sample of gas at 640 mmhg is allowed to expand into a 8.0l container at a constant temperature what is the new pressure

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Answer:

160mmHg

Explanation:

V1 = 2.0L

P1 = 640mmHg

V2 = 8.0L

P2 = ?

This question requires the use of Boyle's law which states that the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.

Mathematically,

V = k / P, k = PV

P1 × V1 = P2 × V2 = P3 × V3 =........Pn × Vn

P1 × V1 = P2 × V2

Solve for P2

P2 = (P1 × V1) / V2

P2 = (640 × 2.0) / 8.0

P2 = 160mmHg

The final pressure of the gas is 160mmHg

The new pressure when 2.0 L sample of gas at 640 mmHg is allowed to expand into a 8.0L container at a constant temperature is 160mmHg.

BOYLE'S LAW:

  • The new pressure of a sample of gas can be calculated by using Boyle's law equation as follows:

P1V1 = P2V2

Where;

  1. P1 = initial pressure (mmHg)
  2. P2 = final pressure (mmHg)
  3. V1 = initial volume (L)
  4. V2 = final volume (L)

  • According to this question, a 2.0L sample of gas at 640 mmHg is allowed to expand into a 8.0L container at a constant temperature. The new pressure can be calculated as follows:

  • 640 × 2 = P2 × 8

  • 1280 = 8P2

  • P2 = 160mmHg

  • Therefore, the new pressure when 2.0 L sample of gas at 640 mmHg is allowed to expand into a 8.0L container at a constant temperature is 160mmHg.

Learn more about Boyle's law equation at: https://brainly.com/question/1437490?referrer=searchResults