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(45 pts) In which reaction is carbon reduced?


CO(g) + O2(g)CO2(g)


CO2(g) + H2O(l)H2CO3(aq)


CH4(g) + 2O2(g)CO2(g) + 2H2O(l)


C2H2(g) + H2(g)C2H4(g)

Respuesta :

jamesesther1234

Answer:

Reductio is gain of electrons, while oxdation is loss. The oxidtion states of carbon in the reaction will show either of oxidation or reduction occurrence.

[tex]C_{2} H_{2}(g) +H_{2} (g)[/tex] → [tex]C_{2} H_{4}(g)[/tex]

Explanation:

Electrons displacement is explained for each reaction below:

  1. +2 to +4 = loss of 2 more lectrons-------oxidation
  2. +4 throughout reaction----no exchange of electrons
  3. -4 to +4 =  loss of 4 electrons-----oxidation
  4. 0 to -2 = gain of 2 electrons-----reduction

The reaction in which carbon is reduced is

C₂H₂(g) + H₂(g) C₂H₄(g).

The correct option is the last option - C2H2(g) + H2(g)C2H4(g)

Reduction can be defined as the gain of electrons. It can also be defined as the decrease in oxidation number.

and

Oxidation can be defined as the loss of electrons. It can also be defined as the Increase in oxidation number.

Now, we will consider the reactions one after the other

  • For CO(g) + O₂(g) → CO₂(g)

Oxidation number of C in CO is +2 and oxidation number of C in CO₂ is +4. This is an increase in oxidation number. Therefore, carbon is oxidized.

  • For CO₂(g) + H₂O(l) → H₂CO₃(aq)

The oxidation number of C in CO₂ and H₂CO₃ is +4. Therefore, the reaction is NOT a redox reaction.

  • For CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l)

The oxidation number of C in CH₄ is -4 and the oxidation number of C in CO₂ is +4. This is an increase in oxidation number. Therefore, carbon is oxidized.

  • For C₂H₂(g) + H₂(g) → C₂H₄(g)

The oxidation number of C in C₂H₂ in -1 and the oxidation number of C in C₂H₄ is -2. This is a decrease in oxidation number. Therefore, carbon is reduced.

Hence, the reaction in which carbon is reduced is

C₂H₂(g) + H₂(g) C₂H₄(g).

The correct option is the last option - C2H2(g) + H2(g)C2H4(g)

Learn more here: https://brainly.com/question/12913997

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