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The equation of the polynomial function is: f(x) = (x + (2 + i))(x + (2 – i))(x + 5) f(x) = (x – (2 + i))(x – (2 – i))(x – 5) f(x) = (x – (2 + i))(x – (2 – i)) f(x) = (x + (2 + i))(x – (2 – i))(x – 5)

Respuesta :

zacharyfinkenbiner

Answer:

A

Step-by-step explanation:

I just did it on Edge 2020, so if the question is;

Now, suppose one of the roots of the polynomial function is irrational. The roots of the function are 2, Square root of 3, and 5. Write the equation for this polynomial function.

Which of the following must also be a root of the function?

–2

- Square root of 3

–5

Square root of 2

This answer is B

The equation of the polynomial function is:

-  (x-2) (x -5)

 - (x-2) (x-3)

 - (x - root 3)

- (x +2) (x+5)

the second question answer is A

MrRoyal

The equation of the polynomial function is: [tex]\mathbf{f(x) = (x + (2 + i))(x + (2 - i))(x +5)}[/tex]

The roots of the equation are given as:

[tex]\mathbf{Roots = -2 - i, -2 + i, -5}[/tex]

Given the roots of a polynomial, the polynomial function is calculated as:

[tex]\mathbf{f(x) = x - Roots}[/tex]

So, we have:

[tex]\mathbf{f(x) = (x - (-2 - i))(x - (-2 + i))(x - (-5))}[/tex]

Evaluate the brackets

[tex]\mathbf{f(x) = (x + (2 + i))(x + (2 - i))(x +5)}[/tex]

Hence, the equation of the polynomial function is: [tex]\mathbf{f(x) = (x + (2 + i))(x + (2 - i))(x +5)}[/tex]

Read more about polynomial functions at:

https://brainly.com/question/17236386

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