Will give the first answer brainliest. Picture attached.

Answer:
2699.73661Ω or 2.697kΩ
Explanation:
[tex]V=IR[/tex]
So...
[tex]R=\frac{V}{I}[/tex]
So...
[tex]\frac{12.3}{0.004556} = 2699.73661[/tex]Ω
This is the answer, but the resistance is much too high for a circuit like this