Can someone please help actually and not put a random answer please it’s due at 12:00 I’ll give brainliest

Answer:
1)(-3,4)
2)2
3)(x-0)^2+(y+5)^2=14
Step-by-step explanation:
1) so the center of a circle equation is (x-h)^2+(y-k)^2=r^2
where (h,k) are center of the circle
so as h we have 3.....but since its -h we must take -3 as x coordinate for center
and we need to take 4 as y coordinate since its -k and k=4 so-(-4)=4
center of circle: (-3,4)
since r^2represents the radius in a circle, the r^2 value is 4
to find just r we must take the square root
sqrt of 4=2
hence radius is 2
(x-0)^2+(y--5)^2=14
Answer:
1)(-3,4)
2)2
3)(x-0)^2+(y+5)^2=14
Step-by-step explanation:
1) so the center of a circle equation is (x-h)^2+(y-k)^2=r^2
where (h,k) are center of the circle
so as h we have 3.....but since its -h we must take -3 as x coordinate for center
and we need to take 4 as y coordinate since its -k and k=4 so-(-4)=4
center of circle: (-3,4)
since r^2represents the radius in a circle, the r^2 value is 4
to find just r we must take the square root
sqrt of 4=2
hence radius is 2
(x-0)^2+(y--5)^2=14
Step-by-step explanation: