Answer: There are [tex]1.415\times 10^{23}[/tex] molecules in 25.4 g of [tex]N_2O_5[/tex]
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{25.4g}{108g/mol}=0.235moles[/tex]
1 mole of [tex]N_2O_5[/tex] contains = [tex]6.023\times 10^{23}[/tex] molecules
Thus 0.235 moles of [tex]N_2O_5[/tex] contains = [tex]\frac{6.023\times 10^{23}}{1}\times 0.235=1.415\times 10^{23}[/tex] molecules.
There are [tex]1.415\times 10^{23}[/tex] molecules in 25.4 g of [tex]N_2O_5[/tex]
