We have been given two similar triangles. We are asked to find the length of segment EF.
We know that corresponding sides of similar triangles are proportional, so we will use proportion to solve our given problem.
[tex]\frac{EF}{DF}=\frac{BC}{AC}[/tex]
Upon substituting measure of our given side lengths, we will get:
[tex]\frac{EF}{1}=\frac{5}{13}[/tex]
[tex]EF=\frac{5}{13}[/tex]
Therefore, the length of segment EF is [tex]\frac{5}{13}[/tex] units.
