Answer:
[tex]381.5\,\,\,ft[/tex]
Step-by-step explanation:
Given: Figure
To find: distance from the right center field fence to third base
Solution:
In a right angled triangle,
using Pythagoras theorem, square of hypotenuse is equal to sum of squares of base and perpendicular.
In ΔBAC,
[tex]BC^2=AB^2+AC^2\\(392)^2=x^2+(90)^2\\153664=x^2+8100\\153664-8100=x^2\\145564=x^2\\\sqrt{145564}=x\\381.5\,\,\,ft=x[/tex]
So,
distance from the right center field fence to third base is 381.5 foot.
