On a coordinate plane, parallelogram A B C D has points (3, 6), (6, 5), (5, 1), and (2, 2).
What is the area of parallelogram ABCD?

Respuesta :

Answer: The area is about  13.01.

Step-by-step explanation:

so to do this we need to find the distance between these  points.And we do that by using the Pythagorean rule a^2 + b^2=C^2

(3,6) and (6,5)

3^2  + 1^2 = c^2

c= [tex]\sqrt{10}[/tex]

(6,5) and (5,1)

1^2 + 4^2= [tex]\sqrt{17}[/tex]

[tex]\sqrt{10} * \sqrt{17}[/tex]= 13.038