Answer: There are [tex]28.303 \times 10^{23}[/tex] atoms in 4.7 moles of calcium.
Explanation:
According to Avogardo's number for every 1 mole of a substance there will be [tex]6.022 \times 10^{23}[/tex] atoms.
For the given Ca atom there are 4.7 moles. Hence the number of atoms present in 4.7 moles will be calculated as follows.
Moles present = [tex]4.7 \times 6.022 \times 10^{23}[/tex] atoms
= [tex]28.303 \times 10^{23}[/tex] atoms
Thus, we can conclude that there are [tex]28.303 \times 10^{23}[/tex] atoms in 4.7 moles of calcium.
