Answer:
Step-by-step explanation:
Given the equation [tex]\frac{1}{3}(x+9) = -12[/tex]
Step 1;
Expand the bracket at the right hand side of the equation to have:
[tex]\frac{1}{3}x +\frac{1}{3}(9) = -12\\\frac{1}{3}x+3=-12\\subtracting\ 3\ from\ both\ sides\\\frac{1}{3}x+3-3=-12-3\\\frac{1}{3}x=-15\\[/tex]
Taking the reciprocal of both sides:
[tex]\frac{3}{x} = \frac{-1}{15} \\ cross\ multiplying\\-x =45\\x=-45[/tex]
