Answer:
3 units
Step-by-step explanation:
Distance between two points (x1,y1) and (x2,y2) on coordinate plane is given by
distance = [tex]\sqrt{(x1-x2)^2 +(y1-y2)^2 }[/tex]
Given points in the problem are (3,-5) and (3,-2).
Thus distance between points (3,-5) and (3,-2).
[tex]distance = \sqrt{(x1-x2)^2 +(y1-y2)^2 }\\=>distance = \sqrt{(3-3)^2 +(-5-(-2))^2 }\\=>distance = \sqrt{(0)^2 +(-5+2)^2 }\\\\=>distance = \sqrt{0 +(-3)^2 }\\\\=>distance = \sqrt{9 }\\=>distance = 3[/tex]
Distance between points (3,-5) and (3,-2) is 3 units
