Perimeter = 68 Units
Answer:
AC = 30 Units
Step-by-step explanation:
The diagonals AC and BD of parallelogram ABCD are bisecting each other by making 90° angle, this tells us that it is a RHOMBUS.
All sides of rhombus are congruent.
AB = 17 units....(given)
Therefore,
Perimeter = 4*17 = 68 Units
Let diagonals AC and BD intersects at point O.
Therefore, by Pythagoras theorem:
[tex]OA^2 = AB^2 - OB^2 \\ OA= \sqrt{AB^2 - OB^2 } \\ = \sqrt{ {17}^{2} - {8}^{2} } \\ = \sqrt{289 - 64} \\ = \sqrt{225} \\ = 15 \\ \because \: AC = 2\times OA \\ \therefore \: AC = 2\times 15 \\ \therefore \: AC = 30 \: units \\ [/tex]
