Respuesta :
We have been given that angle D is an acute angle such that [tex]\sin(\angle D)=0.19[/tex]. We are asked to find the measure of angle D using calculator.
We will use arcsin to solve for angle D.
[tex]\angle D=\sin^{-1}(0.19)[/tex]
Using calculator, we will get:
[tex]\angle D=10.952784198891^{\circ}[/tex]
Upon rounding to nearest tenth of degree, we will get:
[tex]\angle D\approx 11.0^{\circ}[/tex]
Therefore, the measure of angle D is approximately [tex]11.0^{\circ}[/tex].
The value of angle D to the nearest tenth of degree is 11.0°
Acute angles
Acute angles are angles that measures less than 90 degrees. Therefore, angle D measures less than 90 degrees.
According to the question,
- sin D = 0.19
Therefore, the angle D can be found below;
sin D = 0.19
D = sin⁻¹ 0.19
D = 10.9527841989
The angle D to the nearest tenth of degree is as follows;
- D = 11.0°
learn more on acute angles here:https://brainly.com/question/2761036
